Concise branching

Your solution to the previous exercise probably looks like this:

impl Ticket {
    pub fn assigned_to(&self) -> &str {
        match &self.status {
            Status::InProgress { assigned_to } => assigned_to,
            Status::Done | Status::ToDo => {
                panic!(
                    "Only `In-Progress` tickets can be \
                    assigned to someone"
                )
            }
        }
    }
}

You only care about the Status::InProgress variant. Do you really need to match on all the other variants?

New constructs to the rescue!

if let

The if let construct allows you to match on a single variant of an enum, without having to handle all the other variants.

Here's how you can use if let to simplify the assigned_to method:

impl Ticket {
    pub fn assigned_to(&self) -> &str {
        if let Status::InProgress { assigned_to } = &self.status {
            assigned_to
        } else {
            panic!(
                "Only `In-Progress` tickets can be assigned to someone"
            );
        }
    }
}

let/else

If the else branch is meant to return early (a panic counts as returning early!), you can use the let/else construct:

impl Ticket {
    pub fn assigned_to(&self) -> &str {
        let Status::InProgress { assigned_to } = &self.status else {
            panic!(
                "Only `In-Progress` tickets can be assigned to someone"
            );
        };
        assigned_to
    }
}

It allows you to assign the destructured variable without incurring any "right drift", i.e. the variable is assigned at the same indentation level as the code that precedes it.

Style

Both if let and let/else are idiomatic Rust constructs.
Use them as you see fit to improve the readability of your code, but don't overdo it: match is always there when you need it.

Exercise

The exercise for this section is located in 05_ticket_v2/04_if_let